document.write( "Question 675437: Verify that each equation is an identity.\r
\n" ); document.write( "\n" ); document.write( "\"cos%28alpha-beta%29%2Fcos%28alpha%29sin%28beta%29\" = tan(alpha)+cot(beta)
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Algebra.Com's Answer #419843 by jsmallt9(3758)\"\" \"About 
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\"cos%28alpha-beta%29%2Fcos%28alpha%29sin%28beta%29+=+tan%28alpha%29%2Bcot%28beta%29\"
\n" ); document.write( "Since the arguments on the right side are just \"alpha\" and \"beta\", I'm going to use the cos(A-B) formula on the numerator of the left side so that all the arguments are \"alpha\" or \"beta\":
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\n" ); document.write( "Since the right side has two terms I'm going to split the fraction on the left into two terms:
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\n" ); document.write( "Each of the new fractions will reduce:
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\n" ); document.write( "The first fraction is cot and the second is tan:
\n" ); document.write( "\"cot%28beta%29+%2B+tan%28alpha%29+=+tan%28alpha%29%2Bcot%28beta%29\"

\n" ); document.write( "Since addition is commutative we can change the order:
\n" ); document.write( "\"tan%28alpha%29+%2B+cot%28beta%29+=+tan%28alpha%29%2Bcot%28beta%29\"
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