document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=675413>Question 675413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 19 cm. Find all possible values for the length of the rectangle if the perimeter is at least 524 cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419820 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2W\r<BR>\n" );
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document.write( "W = 19\r<BR>\n" );
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document.write( "P >= 524\r<BR>\n" );
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document.write( "2L + 2W >= 524\r<BR>\n" );
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document.write( "2L + 2(19) >= 524\r<BR>\n" );
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document.write( "2L + 38 >= 524\r<BR>\n" );
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document.write( "2L >= 524 - 38\r<BR>\n" );
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document.write( "2L >= 486\r<BR>\n" );
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document.write( "L >= 486/2\r<BR>\n" );
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document.write( "L >= 243\r<BR>\n" );
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document.write( "So if the perimeter is at least 524 cm, then the length is at least 243 cm. </SPAN>\n" );
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