document.write( "Question 61047: How many liters of a 14% alcohol solution must be mixed with 20 liters of a 50% solution to get a 30% solution?\r
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Algebra.Com's Answer #41980 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .14X+.5*20=(X+20).3 \n" ); document.write( ".14X+10=.3X+6 \n" ); document.write( ".14X-.3X=6-10 \n" ); document.write( "-.16X=-4 \n" ); document.write( "X=-4/-.16 \n" ); document.write( "X=25 LITERS OF 14% ALCOHOL. \n" ); document.write( " |