document.write( "Question 675342: Find the exact value of the trigonometric function given that sin u = 12/13 and cos v = -4/5. (Both u and v are in Quadrant II.)
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document.write( "cos(u − v) \n" );
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Algebra.Com's Answer #419767 by sachi(548)![]() ![]() You can put this solution on YOUR website! Both u and v are in Quadrant II \n" ); document.write( "sin u = 12/13 ,so cos u=sqrt((1-(12/13)^2)=-5/13 \n" ); document.write( "and cos v = -4/5. so sin v=sqrt((1-(-4/5)^2)=3/5 \n" ); document.write( "so cos(u − v)=cos u cos v+sin u sin v=-5/13*-4/5+12/13*3/5=(20+36)/65=56/65 \n" ); document.write( "ans \n" ); document.write( " |