document.write( "Question 675341: Barney has some money.
\n" ); document.write( "He spends £10 on a meal and then one-quarter of what he has left on a taxi home. He now has half of what he started with.
\n" ); document.write( "How much did Barney have at the start?\r
\n" ); document.write( "\n" ); document.write( "I first thought that since he had half left and said that he spent 1/4 on the taxi, the £10 that he spent on the meal must have also been 1/4 so he must have begun with £40 however compared to the other questions in the homework paper it seemed to obvious? Please help!
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Algebra.Com's Answer #419763 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi
\n" ); document.write( "He spends £10 on a meal and then one-quarter of what he has left on a taxi home.
\n" ); document.write( "He now has half of what the \"highlight%28x%29\"he started with.
\n" ); document.write( "Best to Set it Up Algebraically:
\n" ); document.write( " \"x+-+10+-+%281%2F4%29%28x-10%29+=+%281%2F2%29x\" |Multiplying thru by 4 so as all denominators = 1
\n" ); document.write( " 4x-40 - (x-10) = 2x
\n" ); document.write( " x = £30, amount he started with
\n" ); document.write( "and...
\n" ); document.write( "£30 - £10 - £5 = £15 \n" ); document.write( "
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