document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61054>Question 61054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What quantity of 60% acid solution must be mixed with 30% acid solution to produce 300mL of a 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41973 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of ml of 60% acid solution to be added to (300-x) ml of 30% acid solution to obtain 300 ml of 50% acid solution. Change the percentages to their decimal equivalents.\r<BR>\n" );
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document.write( "0.6x + 0.3(300-x) = 0.5(300) Simplify and solve for x.<BR>\n" );
document.write( "0.6x + 90 - 0.3x = 150<BR>\n" );
document.write( "0.3x + 90 = 150<BR>\n" );
document.write( "0.3x = 60<BR>\n" );
document.write( "x = 200 ml </SPAN>\n" );
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