document.write( "Question 675298: The height of a triangle is 2 units more than its base. If the base is increased by 4 units and the height is decreased by 2 units, the area of the resulting triangle will be 8 square units more than the area of the original triangle. Find the base and the height of the original triangle. \r
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document.write( "I've just learned that this is a quadratic equation and that the formula is A = 1/2bh. Area equals one half the base times height. \r
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document.write( "So, I think its supposed to be 1/2 (x + 4)(x + 2) - 2 = 8. I'm obviously doing something wrong because the instructors answer is that the base is 8 and the height is 10. What did I not do correctly? \n" );
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Algebra.Com's Answer #419707 by lwsshak3(11628) ![]() You can put this solution on YOUR website! The height of a triangle is 2 units more than its base. If the base is increased by 4 units and the height is decreased by 2 units, the area of the resulting triangle will be 8 square units more than the area of the original triangle. Find the base and the height of the original triangle. \n" ); document.write( "** \n" ); document.write( "original triangle: \n" ); document.write( "let x=base \n" ); document.write( "x+2=height \n" ); document.write( "Area=(1/2)(x)(x+2) \n" ); document.write( ".. \n" ); document.write( "2nd triangle: \n" ); document.write( "x+4=base \n" ); document.write( "(x+2)-2=x=height \n" ); document.write( "Area=(1/2)(x+4)(x) \n" ); document.write( ".. \n" ); document.write( "area of 2nd triangle-area of original triangle=8 \n" ); document.write( "(1/2)(x+4)(x)-(1/2)(x)(x+2)=8 \n" ); document.write( "LCD:2 \n" ); document.write( "x(x+4)-x(x+2)=16 \n" ); document.write( "x^2+4x-x^2-2x=16 \n" ); document.write( "2x=16 \n" ); document.write( "x=8 \n" ); document.write( "x+2=10 \n" ); document.write( ".. \n" ); document.write( "base of original triangle=8 units \n" ); document.write( "height of original triangle=10 units\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |