document.write( "Question 675289: Find an equation of the line that is parallel to y=6x-12 and passes through (-4,1) . \n" ); document.write( "
Algebra.Com's Answer #419703 by khurshidi(7)![]() ![]() You can put this solution on YOUR website! Find an equation of the line that is parallel to y=6x-12 and passes through (-4,1)?\r \n" ); document.write( "\n" ); document.write( "Solution: \n" ); document.write( "Given line \n" ); document.write( "y = 6x -12 \n" ); document.write( "or \n" ); document.write( "6x - y -12 = 0 \n" ); document.write( "therefore \n" ); document.write( "Slope of the given line \n" ); document.write( "m1 = - coefficient of x/coefficient of y\r \n" ); document.write( "\n" ); document.write( "coefficient of x = 6, coefficient of y = -1 \n" ); document.write( "so\r \n" ); document.write( "\n" ); document.write( "m1 = 6\r \n" ); document.write( "\n" ); document.write( "since the required line is parallel to the given line\r \n" ); document.write( "\n" ); document.write( "therefore\r \n" ); document.write( "\n" ); document.write( "m1 = m2 (m2 = the slope of required line)\r \n" ); document.write( "\n" ); document.write( "i.e. m2 = 6\r \n" ); document.write( "\n" ); document.write( "since the line passes through (-4, 1)= ( x1, y1)\r \n" ); document.write( "\n" ); document.write( "therefore\r \n" ); document.write( "\n" ); document.write( "y - y1 = m2(x - x1)\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "y - 1 = 6(x + 4)\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "y - 1 = 6x + 24\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "6x - y + 25 = 0 \n" ); document.write( "This is the required equation parallel to the given equation and passes through (-4, 1). \n" ); document.write( " |