document.write( "Question 675289: Find an equation of the line that is parallel to y=6x-12 and passes through (-4,1) . \n" ); document.write( "
Algebra.Com's Answer #419703 by khurshidi(7)\"\" \"About 
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Find an equation of the line that is parallel to y=6x-12 and passes through (-4,1)?\r
\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "Given line
\n" ); document.write( "y = 6x -12
\n" ); document.write( "or
\n" ); document.write( "6x - y -12 = 0
\n" ); document.write( "therefore
\n" ); document.write( "Slope of the given line
\n" ); document.write( "m1 = - coefficient of x/coefficient of y\r
\n" ); document.write( "\n" ); document.write( "coefficient of x = 6, coefficient of y = -1
\n" ); document.write( "so\r
\n" ); document.write( "\n" ); document.write( "m1 = 6\r
\n" ); document.write( "\n" ); document.write( "since the required line is parallel to the given line\r
\n" ); document.write( "\n" ); document.write( "therefore\r
\n" ); document.write( "\n" ); document.write( "m1 = m2 (m2 = the slope of required line)\r
\n" ); document.write( "\n" ); document.write( "i.e. m2 = 6\r
\n" ); document.write( "\n" ); document.write( "since the line passes through (-4, 1)= ( x1, y1)\r
\n" ); document.write( "\n" ); document.write( "therefore\r
\n" ); document.write( "\n" ); document.write( "y - y1 = m2(x - x1)\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "y - 1 = 6(x + 4)\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "y - 1 = 6x + 24\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "6x - y + 25 = 0
\n" ); document.write( "This is the required equation parallel to the given equation and passes through (-4, 1).
\n" ); document.write( "
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