document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=675306>Question 675306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how can I write -2x^2+12x+12 in standard form? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419702 by </B><A HREF=/tutors/aboutme.mpl?userid=khurshidi><B>khurshidi(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khurshidi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=khurshidi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the question is -2x^2+12x+12=0<BR>\n" );
document.write( "Then you can take '-2' as common from the equation<BR>\n" );
document.write( "i.e.<BR>\n" );
document.write( "          -2(x^2-6x-6)=0<BR>\n" );
document.write( "-2 will go to the right hand side in the denominator of zero and will become zero, <BR>\n" );
document.write( "so the equation will become<BR>\n" );
document.write( "            x^2 - 6x - 6 = 0<BR>\n" );
document.write( "or          x^2 + (-6)x + (-6) = 0<BR>\n" );
document.write( "This is the standard form of quadratic equation. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );