document.write( "Question 675221: Two brothers leave from the same point driving in opposite directions, the first brother driving at 60 miles per hour and the second driving at 45 mph. The first brother has a one hour head start. How long will they be able to talk on their car phones if the phones have a 260 mile-range? \n" ); document.write( "
Algebra.Com's Answer #419696 by josmiceli(19441)\"\" \"About 
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The 1st brother's head start is \"+60%2A1+=+60+\" mi
\n" ); document.write( "You can start a stop watch when the 2nd brother leaves
\n" ); document.write( "Let \"+d+\" = the distance the 1st brother will now travel
\n" ); document.write( "\"+200+-+d+\" = the distance the 2nd brother will now travel
\n" ); document.write( "Let \"+t+\" = the time it takes for them to be \"+260+-+60+=+200+\"
\n" ); document.write( "miles apart.
\n" ); document.write( "-------------
\n" ); document.write( "1st brother's equation:
\n" ); document.write( "(1) \"+d+=+60t+\"
\n" ); document.write( "2nd brother's equation:
\n" ); document.write( "(2) \"+200+-+d+=+45t+\"
\n" ); document.write( "--------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+200+-+60t+=+45t+\"
\n" ); document.write( "(2) \"+105t+=+200+\"
\n" ); document.write( "(2) \"+t+=+1.9048+\" hrs
\n" ); document.write( "\"+.9048%2A60+=+54.3+\"
\n" ); document.write( "They will be able to talk for 1 + 1 + 54 min
\n" ); document.write( "or 2 hours and 54 minutes\r
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