document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=675272>Question 675272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone assist in helping with this problem?\r<BR>\n" );
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document.write( "3y^2 - 2<BR>\n" );
document.write( "_________<BR>\n" );
document.write( "3y^2 + 10y - 8\r<BR>\n" );
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document.write( "minus\r<BR>\n" );
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document.write( "y + 10<BR>\n" );
document.write( "________<BR>\n" );
document.write( "3y^2 + 10y - 8\r<BR>\n" );
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document.write( "minus\r<BR>\n" );
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document.write( "y^2 - 6y<BR>\n" );
document.write( "_________<BR>\n" );
document.write( "3y^2 + 10y - 8\r<BR>\n" );
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document.write( "Equals = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419684 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3y^2 - 2)/(3y^2 + 10y - 8) <BR>\n" );
document.write( "- (y + 10)/(3y^2 + 10y - 8) <BR>\n" );
document.write( "- (y^2 - 6y)/(3y^2 + 10y - 8)<BR>\n" );
document.write( "------------------------------------- <BR>\n" );
document.write( "The denominators are all the same, so combine the numerators<BR>\n" );
document.write( "over the common denominator::<BR>\n" );
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document.write( "= [3y^2-2-y-10-y^2+6y]/(3y^2+10y-8)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= (2y^2 +5y -12)/(3y^2+10y-8)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "= (2y^2+8y-3y-12)/(3y^2+12y-2y-8)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "= (2y(y+4)-3(y+4))/(3y(y+4)-2(y+4))<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "= [(y+4)(2y-3)]/[(y+4)(3y-2)]<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "= (2y-3)/(3y-2)<BR>\n" );
document.write( "========================<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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