document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61058>Question 61058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 36 ft and the width is 10 ft, find its length.  [Hint: The perimeter of a rectangle is given by P = 2L + 2W.] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41967 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 36=2L+2*10<BR>\n" );
document.write( "2L=36-20<BR>\n" );
document.write( "2L=16<BR>\n" );
document.write( "L=16/2<BR>\n" );
document.write( "L=8<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "36=2*8+2+10<BR>\n" );
document.write( "36=16+20<BR>\n" );
document.write( "36=36 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );