document.write( "Question 675254: Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16\r
\n" ); document.write( "\n" ); document.write( "Can you help me figure out this problem? I have tried to get help from a tutor. We worked it out together and we both came up with the same thing that was not an answer choice. I sure would appreciate your help. \n" ); document.write( "

Algebra.Com's Answer #419668 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
2^(8+4x) = 1/16
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\n" ); document.write( "Actually $\"1%2F16+=+2%5E-4\"$
\n" ); document.write( "so we have an equiv equation of:
\n" ); document.write( " $\"2%5E%28%288%2B4x%29%29+=+2%5E-4\"$
\n" ); document.write( "It the bases are equal, the exponents are equal, so we have:
\n" ); document.write( "8 + 4x = -4
\n" ); document.write( "4x = -4 - 8
\n" ); document.write( "4x = -12
\n" ); document.write( "x = -12/4
\n" ); document.write( "x = -3
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\n" ); document.write( "Check this in your calc: enter 2^(8+4(-3)) results: .0625 which is 1/16 \n" ); document.write( "

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