document.write( "Question 675252: I really need help. I do not understand how to solve this at all:
\n" ); document.write( "A man invests his savings in 2 accounts, one paying ^5 per year and the other %. He has twice as much invested in the 7% account as in the 6% account, and his annual interest income is $600. How much is invested in each account?
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Algebra.Com's Answer #419667 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
Establish variables
\n" ); document.write( "x = $ in 6% account
\n" ); document.write( "y = $ in 7% account
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\n" ); document.write( "y = 2x
\n" ); document.write( ".06x + .07y = 600
\n" ); document.write( "...
\n" ); document.write( "Substitute 2x for y in the second equation
\n" ); document.write( ".06x + .07(2x) = 600
\n" ); document.write( ".06x + .14x = 600
\n" ); document.write( ".2x = 600
\n" ); document.write( "\"highlight_green%28x+=+3000%29\" at 6%
\n" ); document.write( "...
\n" ); document.write( "\"highlight_green%28y+=+2%283000%29+=+6000%29\" at 7%
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\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
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