document.write( "Question 675212: The perimeter of a rectangle is 34 inches, and its area is 70 square inches. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #419632 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "P=34 \n" ); document.write( "34=2L+2W \n" ); document.write( "2L=-2W+34 \n" ); document.write( "L=-2W/2+34/2 \n" ); document.write( "L=-W+17 \n" ); document.write( "A=LW \n" ); document.write( "70=(-w+17)W \n" ); document.write( "70=-W^2+17W \n" ); document.write( "W^2-17W+70=0 \n" ); document.write( "(W-10)(W-7)=0 \n" ); document.write( "W-10=0 \n" ); document.write( "W=10 ANS. & LENGTH IS 7. \n" ); document.write( "W-7=0 \n" ); document.write( "W=7 ANS. & LENGTH IS 10. \n" ); document.write( "PROOF: \n" ); document.write( "34=2*7+2*7 \n" ); document.write( "34=14+20 \n" ); document.write( "34=34 \n" ); document.write( "70=7*10 \n" ); document.write( "70=70 \n" ); document.write( " \n" ); document.write( " |