document.write( "Question 61028: Would someone mind taking a look at this question and see if my answer is correct. I think I am on the right track.
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document.write( "One needs to mix a 30% acid solution with a 50% acid solution to obtain 12 ounces of a 45% acid solution. How many ounces of each of the acid solutions must be used?\r
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document.write( "Amt. of mix is 12 oz
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document.write( "Amt of 1st acid = x
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document.write( "Amt. of 2nd acid is the rest = 12-x\r
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document.write( "Amt. of acid in the mixture = .45(12)
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document.write( "Amt. of 1st acid = .30x
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document.write( "Amt. of 2nd acid = .50(12-x)\r
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document.write( "3 oz of 30% acid
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document.write( "9 oz of 50% acid \n" );
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Algebra.Com's Answer #41962 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! You are right with your answers, and I like your \n" ); document.write( "approach better than mine, in fact. \n" ); document.write( "I used two variables where you only used one. \n" ); document.write( "Amt. of mix is 12 oz \n" ); document.write( "Amt of 1st acid = x \n" ); document.write( "Amt. of 2nd acid is the rest = y (you said (12-x)) \n" ); document.write( "Amt. of acid in the mixture = .45(12) \n" ); document.write( "Amt. of 1st acid = .30x \n" ); document.write( "Amt. of 2nd acid = .50y \n" ); document.write( ".30x + .50y = .45*12 \n" ); document.write( "x + y = 12 \n" ); document.write( ".30x + .50(12-x) = .45*12 \n" ); document.write( ".3x + 6 - .5X = 5.4 \n" ); document.write( ".2x = 6 - 5.4 \n" ); document.write( ".2x = .6 \n" ); document.write( "x = 3 \n" ); document.write( "y = 12 - 3 \n" ); document.write( "y = 9\r \n" ); document.write( "\n" ); document.write( "3 oz of 30% acid \n" ); document.write( "9 oz of 50% acid \n" ); document.write( "you are correct \n" ); document.write( " |