document.write( "Question 675129: x2+12x-5=0
\n" ); document.write( "that is x squared+12x-5=0
\n" ); document.write( "this must be solved by the method for solving quadratis equation that came from India, that states-
\n" ); document.write( " it breaks down like this, a) move the constant term to the right side of the equation, b) multiply each term in the equation by four times the coefficient of the X squared term, c) squared the coefficient of the original X term and add it to both sides of the equation, D) take the square root of both sides, E) set the left side of the equation equal to the positive square root of the number on the right side and solve for x, F) set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for X
\n" ); document.write( "Thank you for your help and please show your work so I can understand how to do this. Thank you. \n" ); document.write( "
Algebra.Com's Answer #419580 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" );
document.write( "Hi
\n" );
document.write( "x2+12x-5=0
\n" );
document.write( "x2+12x = 5
\n" );
document.write( "4x2+48x = 20
\n" );
document.write( "4x2+48x+144 = 164 
\n" );
document.write( "\"sqrt%28%282x%2B12%29%282x%2B12%29%29\" = ħ sqrt(164)
\n" );
document.write( "      2x + 12 = 2sqrt(41)
\n" );
document.write( "           x = -6 +sqrt(41)
\n" );
document.write( "      2x + 12 = -2sqrt(41)
\n" );
document.write( "            x = -6 -sqrt(41)\r
\n" );
document.write( "\n" );
document.write( "Checking using 'Completing the Square'
\n" );
document.write( "(x+6)^2 = 5 + 36
\n" );
document.write( "   x+6 =  ħsqrt(41)
\n" );
document.write( "    x = -6 ħsqrt(41)
\n" );
document.write( "   \n" );
document.write( "
\n" );