document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=675054>Question 675054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Matt is one year older than five times Kelly's age. In three years, Matt will be only three times Kelly's age. How old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419526 by </B><A HREF=/tutors/aboutme.mpl?userid=rm29924><B>rm29924(97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rm29924><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rm29924><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = Kelly's current age<BR>\n" );
document.write( "Matt's current age is 5x+1\r<BR>\n" );
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document.write( "Kelly's age in 3 years = x+3<BR>\n" );
document.write( "Matt's age in 3 years = 5x+1+3\r<BR>\n" );
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document.write( "Matt's age in 3 years = 3 times Kelly's age in 3 years<BR>\n" );
document.write( "5x+1+3 = 3(x+3)<BR>\n" );
document.write( "5x+4=3x+9<BR>\n" );
document.write( "subtract 4 from both sides<BR>\n" );
document.write( "5x=3x+5<BR>\n" );
document.write( "subtract 3x from both sides<BR>\n" );
document.write( "2x=5<BR>\n" );
document.write( "divide both sides by 2 to get x by itself<BR>\n" );
document.write( "x=2.5\r<BR>\n" );
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document.write( "answer:  Kelly is 2.5 years old<BR>\n" );
document.write( "Matt is 5(2.5)+1 = 13.5 years old<BR>\n" );
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