document.write( "Question 674803: Dan has nickels, dimes and quarters. He has a total of 33.60. He has four times as many quarters as dimes and one-half as many dimes as nickels. How many of each coin does he have? \r
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document.write( "I put x nickels, y dimes, and z quarters. 5x + 10y + 25z = 3360. Next, I put z = y + 4 to represent \"four times as many quarters as dimes.\" Next, I put either x = 1/2y or x = 0.5y to represent \"one-half as many dimes as nickels. \r
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document.write( "Next, I saw how 1/2y or 0.5y is really 1/2 times 10 or 0.5 times ten which equals five (5). \r
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document.write( "Then I substituted for 5x + 10y + 25z = 3360 by plugging in the numbers as follows: 5(5) + 10y + 25(y+4) = 3360. When I solved it, it wasn't correct. \r
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document.write( "I'm supposed to get 112 quarters, 28 dimes, and 56 nickels. \r
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document.write( "Am I missing a step where I should write x + y + z? - And then substitute one at at time? This is different in that I may not be writing something correctly because this problem contains no amount but only the value as the total and that it contains 1/2 which I may be figuring wrong. Thanks in advance. \n" );
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Algebra.Com's Answer #419446 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Dan has nickels, dimes and quarters. \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement, get n and q in terms of d: \n" ); document.write( ": \n" ); document.write( " He has a total of 33.60. \n" ); document.write( ".05n + .10d + .25q = 33.60 \n" ); document.write( "5n + 10d + 25q = 3360, get rid of the decimals \n" ); document.write( ": \n" ); document.write( " He has four times as many quarters as dimes \n" ); document.write( "q = 4d \n" ); document.write( ": \n" ); document.write( "and one-half as many dimes as nickels. \n" ); document.write( "n = 2d \n" ); document.write( ": \n" ); document.write( "Replace n with 2d, replace q with 4d \n" ); document.write( "5(2d) + 10d + 25(4d) = 3360 \n" ); document.write( "10d + 10d + 100d = 3360 \n" ); document.write( "120d = 3360 \n" ); document.write( "d = 3360/120 \n" ); document.write( "d = 28 dimes \n" ); document.write( ": \n" ); document.write( "See if you can find n and q, and check it in the 1st equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |