document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674831>Question 674831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am coming up with an answer but its from plugging it in a calculator, how do I work this backwards?  I am coming up with x=1.82\r<BR>\n" );
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document.write( "Approximate answer:\r<BR>\n" );
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document.write( "  3*5^(2-x)=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419444 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3*5^(2-x)=4<BR>\n" );
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document.write( "divide both sides by 3<BR>\n" );
document.write( "5^(2-x) = 4/3<BR>\n" );
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document.write( "using logs<BR>\n" );
document.write( "log(5^(2-x)) = log(4/3)<BR>\n" );
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document.write( "log equiv of exponents<BR>\n" );
document.write( "(2-x)*log(5) = log(4/3)<BR>\n" );
document.write( ".69897(2-x) = .1249<BR>\n" );
document.write( "2 - x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.1249%2F.69897 ALIGN=MIDDLE  ALT=\".1249%2F.69897\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2 - x = .1787<BR>\n" );
document.write( "2 - .1787 = x<BR>\n" );
document.write( "1.82 = x </SPAN>\n" );
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