document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60890>Question 60890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One pipe can fill a tank in 8 minutes and a second pipe can fill it in 12 minutes. If the tank is empty, how long will it take both pipes to fill it?\r<BR>\n" );
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document.write( "Thank you for looking.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41943 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One approach to this kind of problem is to first calculate the rate that each pipe can fill the tank.<BR>\n" );
document.write( "If it takes pipe A 8 minutes to fill the tank, then pipe A can fill 1/8 of the tank in 1 minute.<BR>\n" );
document.write( "If it takes pipe B 12 minutes to fill the tank, then pipe B can fill 1/12 of the tank in 1 minute.<BR>\n" );
document.write( "Working together, pipe A and pipe B can fill (1/8 + 1/12) of the tank in 1 minute.<BR>\n" );
document.write( "1/8 + 1/12 = (3+2)/24 = 5/24 of the tank in 1 minute.<BR>\n" );
document.write( "5/24 of tank = 1 min. Multiply both sides by the reciprocal (24/5)<BR>\n" );
document.write( "1 = 24/5 mins. = 4.8 mins.<BR>\n" );
document.write( "The tank can be filled in 4.8 minutes by both pipes working together. </SPAN>\n" );
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