document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61015>Question 61015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorcycle manufacturer produces three different models: the Avalon, the Durango, and the Roadtripper. Production restrictions require it to make, on a monthly basis, 10 more Roadtrippers than the total of the other two models, and twice as many Durangos as Avalons. The shop must produce a total of 490 cycles per month. How many cycles of each type should be made per month?\r<BR>\n" );
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document.write( "I just don't know how to set it up!!!! Thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41941 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A+D+R=490 GIVEN<BR>\n" );
document.write( "R=10+(A+D) GIVEN<BR>\n" );
document.write( "D=2A GIVEN <BR>\n" );
document.write( "THEN R=10(A+2A) OR<BR>\n" );
document.write( "R=10+(A+2A)<BR>\n" );
document.write( "R=10+3A<BR>\n" );
document.write( "THEN A+(2A)+(10+3A)=490<BR>\n" );
document.write( "A+2A+10+3A=490<BR>\n" );
document.write( "6A=490-10<BR>\n" );
document.write( "6A=480<BR>\n" );
document.write( "A=480/6<BR>\n" );
document.write( "A=80 AVALONS<BR>\n" );
document.write( "D=2*80<BR>\n" );
document.write( "D=160 DURANGOS<BR>\n" );
document.write( "R=10+(80+160)<BR>\n" );
document.write( "R=10+240<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "R=250<BR>\n" );
document.write( "A+D+R=490<BR>\n" );
document.write( "80+160+250=490<BR>\n" );
document.write( "490=490 </SPAN>\n" );
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