document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674652>Question 674652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the number of square units in the area of a triangle whose sides are 5, 6 and &#8730;<span  DISABLED_style= \"text-decoration: overline\">61</span>.  Explain answers in simplest form.  (I think it's 21, but i think it's wrong.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419399 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the number of square units in the area of a triangle whose sides are 5, 6 and &#8730;<span  DISABLED_style= \"text-decoration: overline\">61</span>.  Explain answers in simplest form.  (I think it's 21, but i think it's wrong.)\r<BR>\n" );
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document.write( "You never bothered to share with us how you arrived at 21 sq units. \r<BR>\n" );
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document.write( "However, you need to use the law of cosines formula, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+=+b%5E2+%2B+c%5E2+-+2bc+Cos+A ALIGN=MIDDLE  ALT=\"a%5E2+=+b%5E2+%2B+c%5E2+-+2bc+Cos+A\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "After substituting the sides (based on their angles), into the above-formula, you will derive the degree measure of angle A. \r<BR>\n" );
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document.write( "Using the degree measure of angle A, you can then determine the area of the triangle by applying the following formula for a non-right triangle: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%281%2F2%29bc+Sin+A ALIGN=MIDDLE  ALT=\"A+=+%281%2F2%29bc+Sin+A\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This should give you an area of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15.001 ALIGN=MIDDLE  ALT=\"15.001\"   DISABLED_style= \"max-width:90%; height:auto;\" > &#8776; <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2815%29 ALIGN=MIDDLE  ALT=\"highlight_green%2815%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq units\r<BR>\n" );
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document.write( "OR\r<BR>\n" );
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document.write( "It can be seen that the triangle is actually a right-angled one, so you can use the pythagorean formula: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+%2B+b%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2+%2B+b%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, with c being the longest side, or the hypotenuse of the triangle, represented by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2861%29 ALIGN=MIDDLE  ALT=\"sqrt%2861%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. \r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com </SPAN>\n" );
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