document.write( "Question 60961: If a boat goes downstream 72 miles in 3 hours and upstream 60 miles in 6 hours, the rate of the river and the rate of the boat in still water respectively are? I've got a solution and the answer is correct, but I don't think I worked it out right. \n" ); document.write( "
Algebra.Com's Answer #41939 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! If a boat goes downstream 72 miles in 3 hours and upstream 60 miles in 6 hours, the rate of the river and the rate of the boat in still water respectively are? \n" ); document.write( ": \n" ); document.write( "Let x = speed of boat in still water, Let y = speed of river \n" ); document.write( ": \n" ); document.write( "Make two equations; time * speed = distance: \n" ); document.write( ": \n" ); document.write( "Downstream equation: \n" ); document.write( "3(x + y) = 72\r \n" ); document.write( "\n" ); document.write( "Simplify, divide eq by 3 \n" ); document.write( "x + y = 24 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Upstream equation: \n" ); document.write( "6(x - y) = 60 \n" ); document.write( ": \n" ); document.write( "Simplify divide by 6 \n" ); document.write( "x - y = 10 \n" ); document.write( ": \n" ); document.write( "Use elimination method on the these two equations: \n" ); document.write( "x + y = 24 \n" ); document.write( "x - y = 10 \n" ); document.write( "------------ add \n" ); document.write( "2x + 0 = 34 \n" ); document.write( "x = 34/2 \n" ); document.write( "x = 17 mph, speed of the boat in still water: \n" ); document.write( ": \n" ); document.write( "Find river speed: \n" ); document.write( "17 - y = 10 \n" ); document.write( "y = 7 mph is the rive speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( "3(17+7) = 72 \n" ); document.write( "6(17-7) = 60 \n" ); document.write( ": \n" ); document.write( "Make sense to you? Any questions? \n" ); document.write( " \n" ); document.write( " |