document.write( "Question 674687: I have two questions concerning Logarithms. I appreciate any help.\r
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document.write( "a) Write as a single logarithm:
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document.write( " 2log3^x+log3^y-log3^z\r
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document.write( "this is what I came up with but...?
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document.write( " 2log3^(x+y-z)\r
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document.write( "b) solve for x:
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document.write( " 2log3^(x+7+5) = log4^16 \n" );
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Algebra.Com's Answer #419383 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to write:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use \"the sum of the logs is the log of the product\":\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use \"the difference of the logs is the log of the quotient\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |