document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=672505>Question 672505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ways are there to seat four of a group of ten people around a circular table where two sitting are considered the same when everyone has the same immediate left and immediate right neighbour? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419359 by </B><A HREF=/tutors/aboutme.mpl?userid=chandrumail><B>chandrumail(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chandrumail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 4 people can be chosen from the group of 10 in 10C4 ways = \r<BR>\n" );
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document.write( "10*9*8*7/(4*3*2*1) = 210 ways\r<BR>\n" );
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document.write( "  Since it's a circular arrangement, Each of the 210 different choices of 4 people can be arranged in (4-1)! ways\r<BR>\n" );
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document.write( "Everyone has the same immediate left and immediate right neighbour means the clockwise and anticlockwise arrangement are not same.\r<BR>\n" );
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document.write( "So, total number of ways = 210*3! = 210*6 = 1260 ways<BR>\n" );
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