document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674016>Question 674016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the vertex, focus, directrix and axis of symmetry of each parabola<BR>\n" );
document.write( "6x+y^2=0\r<BR>\n" );
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document.write( "I know (y+0)^2 is part of a formula but what do I do with the 6x since there is no square?\r<BR>\n" );
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document.write( "another problem is x^2=y+2x  Can you tell me how to set this one up?<BR>\n" );
document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419317 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need to find the vertex, focus, directrix and axis of symmetry of each parabola<BR>\n" );
document.write( "6x+y^2=0<BR>\n" );
document.write( "y^2=-6x<BR>\n" );
document.write( "This is an equation of a parabola that open leftwards.<BR>\n" );
document.write( "Its standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex<BR>\n" );
document.write( "For given equation: y^2=-6x<BR>\n" );
document.write( "vertex:(0,0)<BR>\n" );
document.write( "axis of symmetry: y=0<BR>\n" );
document.write( "4p=6<BR>\n" );
document.write( "p=6/4=3/2<BR>\n" );
document.write( "focus: (-3/2,0) (p-distance left of vertex on axis of symmetry<BR>\n" );
document.write( "directrix: x=3 (p-distance right of vertex on axis of symmetry)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x^2=y+2x<BR>\n" );
document.write( "y=x^2-2x<BR>\n" );
document.write( "This is an equation of a parabola that open upwards.<BR>\n" );
document.write( "Its standard form:y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex, A>0, curve opens upwards, A<0, curve opens downwards.<BR>\n" );
document.write( "for given equation: y=x^2-2x<BR>\n" );
document.write( "complete the square<BR>\n" );
document.write( "y=(x^2-2x+1)-1<BR>\n" );
document.write( "y=(x-1)^2-1<BR>\n" );
document.write( "rewrite to standard form of first equation above<BR>\n" );
document.write( "(x-1)^2=(y+1)<BR>\n" );
document.write( "vertex: (1,-1)<BR>\n" );
document.write( "axis of symmetry: x=1<BR>\n" );
document.write( "4p=1<BR>\n" );
document.write( "p=1/4<BR>\n" );
document.write( "focus: (1,-3/4) (p-distance above vertex on axis of symmetry)<BR>\n" );
document.write( "directrix: y=-5/4 (p-distance below vertex on axis of symmetry)<BR>\n" );
document.write( " </SPAN>\n" );
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