document.write( "Question 60957: A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is $91.00. How much is invested at 8%. Can you show me how you work it out and solve it? \n" ); document.write( "
Algebra.Com's Answer #41931 by checkley71(8403)\"\" \"About 
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.10X+.08*2X=9100
\n" ); document.write( ".10X+.16X=9100
\n" ); document.write( ".26X=9100
\n" ); document.write( "X=9100/.26
\n" ); document.write( "X=35000 AMOUNT INVESTED @ 10%
\n" ); document.write( "2*35000=70000 INVESTED @ 8%
\n" ); document.write( "PROOF
\n" ); document.write( "35000*.10+70000*.08=9100
\n" ); document.write( "3500+5600=9100
\n" ); document.write( "9100=9100
\n" ); document.write( "
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