document.write( "Question 674533: Here is the trig problem:\r
\n" ); document.write( "\n" ); document.write( "Derive the identity for tan(a-b)using tan(a-b)=tan[a+(-b)].\r
\n" ); document.write( "\n" ); document.write( "After applying the formula for the tangent of the sum of two angles, use the fact that the tangent is an odd function.
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Algebra.Com's Answer #419307 by lwsshak3(11628)\"\" \"About 
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Derive the identity for tan(a-b)using tan(a-b)=tan[a+(-b)].
\n" ); document.write( "After applying the formula for the tangent of the sum of two angles, use the fact that the tangent is an odd function.
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\n" ); document.write( "if function is even, f(-x)=f(x)
\n" ); document.write( "if function is odd, f(-x)=-f(x)
\n" ); document.write( "tan, being an odd function:
\n" ); document.write( "tan(-x)=-tan(x)
\n" ); document.write( "..
\n" ); document.write( "Identity: tan(a+b)=(tana+tanb)/(1-tana tanb)
\n" ); document.write( "tan[(a+(-b)]=(tana+tan(-b))/(1-tana tan(-b))
\n" ); document.write( "tan(-b)=-tan b
\n" ); document.write( "tan(a-b)=(tana-tanb)/(1+tana tanb)
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