document.write( "Question 60959: The width of a retangle is 15 feet less than its length, and the perimeter is 210 feet. Can you show me how to find the width and the length. \n" ); document.write( "
Algebra.Com's Answer #41930 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! W=L-15 \n" ); document.write( "P=2L+2W \n" ); document.write( "210=2L+2(L-15) \n" ); document.write( "210=2L+2L-30 \n" ); document.write( "4L=210+30 \n" ); document.write( "4L=240 \n" ); document.write( "L=240/4 \n" ); document.write( "L=60 THEN \n" ); document.write( "W=60-15 \n" ); document.write( "W=45 \n" ); document.write( "PROOF \n" ); document.write( "210=2*60+2*45 \n" ); document.write( "210=120+90 \n" ); document.write( "210=210 \n" ); document.write( " |