document.write( "Question 674158: A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. Determine a 68 % confidence interval for the population proportion of college seniors who plan to attend graduate school. (Enter each answer rounded to three decimal places.) \n" ); document.write( "
Algebra.Com's Answer #419262 by stanbon(75887)\"\" \"About 
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A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. Determine a 68 % confidence interval for the population proportion of college seniors who plan to attend graduate school. (Enter each answer rounded to three decimal places.)
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\n" ); document.write( "p-hat = 20/100 = 1/5
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\n" ); document.write( "ME = z*s = 0.9945*sqrt[(1/5)(4/5)/100] = 0.0398
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\n" ); document.write( "68% CI: 0.2-0.0398 < p < 0.2+0.0398
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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