document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674463>Question 674463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> so the equaiton is: measure of angle 2=x+78. The triangles point is 55 degree and thr right side and bottom is the same length. How do I solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419251 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so the equaiton is: measure of angle 2=x+78. The triangles point is 55 degree and thr right side and bottom is the same length. How do I solve this?<BR>\n" );
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document.write( "If 2 sides are the same length, the angles opposite those sides are equal.<BR>\n" );
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document.write( "You are given that the vertex angle is 55 degrees.<BR>\n" );
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document.write( "The sum of the 2 base angles is 180-55 = 125 degrees<BR>\n" );
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document.write( "Each base angle is 125/2 = 62.5 degrees<BR>\n" );
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document.write( "Note: I don't know where your #2 angle is.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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