document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60997>Question 60997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Roland traveled from Nashville to St. Louis, a distance of 300 miles. If he had increased his speed by 10 mph he would have arrived at St. Louis an hour and 30 minutes sooner.  What was his speed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41925 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 300=rt or r=300/t<BR>\n" );
document.write( "300=(r+10)(t-1.5) now substitute (300/t) for r in the second equation we get<BR>\n" );
document.write( "300=(300/t+10)(t-1.5)<BR>\n" );
document.write( "300=(300/t*t)+10*t+(300/t*-1.5)+(10*-1.5)<BR>\n" );
document.write( "300=300+10t-450/t-15<BR>\n" );
document.write( "0=10t-450/t-15<BR>\n" );
document.write( "0=(10t^2-450-15t)/t<BR>\n" );
document.write( "0=10t^2-15t-450<BR>\n" );
document.write( "(5t+30)(2t-15)=0<BR>\n" );
document.write( "5t+30=0<BR>\n" );
document.write( "5t=-30<BR>\n" );
document.write( "t=-30/5<BR>\n" );
document.write( "t=-6<BR>\n" );
document.write( "2t-15=0<BR>\n" );
document.write( "2t=15<BR>\n" );
document.write( "t=15/2<BR>\n" );
document.write( "t=7.5 hours then<BR>\n" );
document.write( "300=r*7.5<BR>\n" );
document.write( "r=300/7.5<BR>\n" );
document.write( "r=40 mph speed of trip<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );