document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674412>Question 674412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hala can ride her bike 7 and 1/2 miles in 1 hour. how many can she ride in 3 hours? how many can she ride in 2/3 of an hour?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419223 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance  = rate x time<BR>\n" );
document.write( "Her rate is 7 and 1/2 miles per hour<BR>\n" );
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document.write( "D = ( 7 + 1/2 miles/hr ) x ( 3 hrs )<BR>\n" );
document.write( "D = 21 + 3/2 miles<BR>\n" );
document.write( "D = 22 + 1/2 miles<BR>\n" );
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document.write( "D = ( 7 + 1/2  miles/hr ) x 2/3 hr<BR>\n" );
document.write( "D = 14/3 + 2/6 miles<BR>\n" );
document.write( "D = 14/3 + 1/3 miles<BR>\n" );
document.write( "D = 4 + 2/3 + 1/3 miles<BR>\n" );
document.write( "D = 5 miles<BR>\n" );
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