document.write( "Question 674383: how do you substitute:\r
\n" ); document.write( "\n" ); document.write( "3u + 8 = 4v
\n" ); document.write( "24v = 6 - 3u
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Algebra.Com's Answer #419207 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
(1) \"+3u+%2B+8+=+4v+\"
\n" ); document.write( "(2) \"+24v+=+6+-+3u+\"
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\n" ); document.write( "(2) \"+24v+-+6+=+-3u+\"
\n" ); document.write( "(2) \"+-24v+%2B+6+=+3u+\"
\n" ); document.write( "Substitute \"+3u+\" in (2) in place
\n" ); document.write( "of \"+3u+\" in (1)
\n" ); document.write( "(1) \"+-24v+%2B+6+%2B+8+=+4v+\"
\n" ); document.write( "(1) \"+28v+=+14+\"
\n" ); document.write( "(1) \"+v+=+1%2F2+\"
\n" ); document.write( "Plug this back into (1)
\n" ); document.write( "(1) \"+3u+%2B+8+=+4%2A%281%2F2%29+\"
\n" ); document.write( "(1) \"+3u+=+2+-+8+\"
\n" ); document.write( "(1) \"+3u+=+-6+\"
\n" ); document.write( "(1) \"+u+=+-2+\"\r
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