document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674350>Question 674350</A>: <I><SPAN STYLE=\"word-break: break-all;\">  In years, how old was the older person when you were born?<BR>\n" );
document.write( "28 (Myself)<BR>\n" );
document.write( "10 (brother)<BR>\n" );
document.write( "50 (mother)<BR>\n" );
document.write( "  <BR>\n" );
document.write( " Write an equation that models how old in years each of you will be, when your ages add up to 150 years old. For example, if x = your age and the eldest person was a year older than you, you would write their age as x + 1. Then the equation would be: x + (x+1) = 150.<BR>\n" );
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document.write( "Explain the reasoning which helped you develop your equation.<BR>\n" );
document.write( "    Solve for your future ages. Are your answers reasonable, do they add up to 150? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419183 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = your age now.<BR>\n" );
document.write( "your brother's age is x - 18 now because x - 18 = 10<BR>\n" );
document.write( "your mother's age is x + 22 now because x + 22 = 50<BR>\n" );
document.write( "you want to find out how old each of you will be when the sum of your ages is 150.<BR>\n" );
document.write( "the equation would be x + x - 18 + x + 22 = 150<BR>\n" );
document.write( "combine like terms to get 3x + 4 = 150<BR>\n" );
document.write( "subtract 4 from both sides of the equation to get 3x = 146<BR>\n" );
document.write( "divide both sides of the equation by 3 to get x = 146/3<BR>\n" );
document.write( "when the sum of your ages is 150, you will be 146/3 years old, your brother will be 146/3 - 18 years old, and your mother will be 146/3 + 22 years old.<BR>\n" );
document.write( "in decimal terms, that means:<BR>\n" );
document.write( "you will be 48.67 years old<BR>\n" );
document.write( "your brother will be 30.67 years old<BR>\n" );
document.write( "your mother will be 70.67 years old<BR>\n" );
document.write( "add them up and they equal 150.01 which is the same as 150 if we ignore the rounding error.<BR>\n" );
document.write( "the older person is 50 years old.<BR>\n" );
document.write( "you are 28.<BR>\n" );
document.write( "when you were born, the older person was 28 years younger which makes the older person 50 - 28 = 22.<BR>\n" );
document.write( "your mother was 22 when you were born.<BR>\n" );
document.write( "your age is now x.<BR>\n" );
document.write( "your mother's age is x + 22.<BR>\n" );
document.write( "when x is equal to 0, x + 22 is equal to 22 so it check out.<BR>\n" );
document.write( "the reasoning behind this is that we are taking your age as the base and everything else is relative to that base.<BR>\n" );
document.write( "the difference between their age and your is constant which allows the equatins to work regardless of your age.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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