document.write( "Question 674338: A goes down river 9 miles, then back upriver for 3 miles. Rate of river current is 6 mph. How long does it take A to go the 12 miles? I have 9/x-6 for time downstream, and 3/x-6 for time upstream, but don't know how to set up the equation. (Answer is 1 hour.) \n" ); document.write( "
Algebra.Com's Answer #419167 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
let \"+r+\" = A's rate in still water ( no current )
\n" ); document.write( "Going downstream, his rate is \"+r+%2B+6+\"
\n" ); document.write( "Going upstream, his rate is \"+r+-+6+\"
\n" ); document.write( "---------------
\n" ); document.write( "Going downstream,
\n" ); document.write( "\"+9+=+%28+r+%2B+6+%29%2At%5B1%5D+\"
\n" ); document.write( "Going upstream,
\n" ); document.write( "\"+3+=+%28+r+-+6+%29%2At%5B2%5D+\"
\n" ); document.write( "-------------------
\n" ); document.write( "You need to find \"+t%5B1%5D+%2B+1%5B2%5D+\"
\n" ); document.write( "\"+t%5B1%5D+=+9+%2F+%28+r+%2B+6+%29+\"
\n" ); document.write( "\"+t%5B2%5D+=+3+%2F+%28+r+-+6+%29+\"
\n" ); document.write( "--------------------
\n" ); document.write( "\"+t%5B1%5D+%2B+t%5B2%5D+=+9%2F%28+r+%2B+6+%29+%2B+3%2F%28+r+-+6+%29+\"
\n" ); document.write( "I think you're missing his rate in still water
\n" ); document.write( "Can't solve without it.\r
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