document.write( "Question 674291: What is the solution?
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document.write( "x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12 \n" );
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Algebra.Com's Answer #419152 by jokaehler(26)![]() ![]() You can put this solution on YOUR website! x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First, we need to use the distributive property on the left side of the equation. (x * 3) + (x * -x) + (2x * x) + (2x * -1) \r \n" ); document.write( "\n" ); document.write( "Which turns out to be...\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, we need to get \"x\" on one side (I like \"x\" on the left side). Subtract \" \n" ); document.write( "\n" ); document.write( "We end up with...\r \n" ); document.write( "\n" ); document.write( "4x (is less than or equal to) 12 \r \n" ); document.write( "\n" ); document.write( "Divide both sides by \"4,\" and we end up with...\r \n" ); document.write( "\n" ); document.write( "x (is less than or equal to) 3 \n" ); document.write( " |