document.write( "Question 674291: What is the solution?
\n" ); document.write( "x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12
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Algebra.Com's Answer #419152 by jokaehler(26)\"\" \"About 
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x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12 \r
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\n" ); document.write( "\n" ); document.write( "First, we need to use the distributive property on the left side of the equation. (x * 3) + (x * -x) + (2x * x) + (2x * -1) \r
\n" ); document.write( "\n" ); document.write( "Which turns out to be...\r
\n" ); document.write( "\n" ); document.write( "\"+3x+-+x%5E2+%2B+2x%5E2+-+2x+%28is+less+than+or+equal+to%29+x%5E2+-+3x+%2B+12+\"\r
\n" ); document.write( "\n" ); document.write( "Then, we need to get \"x\" on one side (I like \"x\" on the left side). Subtract \"\"+x%5E2+\"\" and add \"\"+3x+\"\" to both sides. \r
\n" ); document.write( "\n" ); document.write( "We end up with...\r
\n" ); document.write( "\n" ); document.write( "4x (is less than or equal to) 12 \r
\n" ); document.write( "\n" ); document.write( "Divide both sides by \"4,\" and we end up with...\r
\n" ); document.write( "\n" ); document.write( "x (is less than or equal to) 3
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