document.write( "Question 60963This question is from textbook Algebra for College Students
\n" ); document.write( ": A rectangular piece of cardboard is 2 units longer than it is wide. From each of its corners a square piece 2 units on a side is cut out. The flaps are then turned up to form an open box that has a volume of 70 cubic units. Find the length and width of the original piece of cardboard. \n" ); document.write( "
Algebra.Com's Answer #41915 by Earlsdon(6294)\"\" \"About 
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Let x = the width of the original piece of cardboard. Then its length is x+2
\n" ); document.write( "If you were to cut out 2-unit squares from each corner and then fold up the flaps to create an open box, the width of the open box would be (x-4) and its length would be ((x+2)-4), and its height would, of course, be 2.
\n" ); document.write( "Now you can write the equation for the volume of the box as:
\n" ); document.write( "\"V+=+%28x-4%29%28%28x%2B2%29-4%29%282%29\" But the volume is given as 70 cubic units, so:
\n" ); document.write( "\"%28x-4%29%28%28x%2B2%29-4%29%282%29+=+70\" Simplify and solve for x.
\n" ); document.write( "\"%28x-4%29%28x-2%29%282%29+=+70\"
\n" ); document.write( "\"%28x%5E2-6x%2B8%29%282%29+=+70\" Divide both sides by 2.
\n" ); document.write( "\"x%5E2-6x%2B8+=+35\" Subtract 35 from both sides.
\n" ); document.write( "\"x%5E2-6x-27+=+0\" Solve this quadratic equation for x by factoring.
\n" ); document.write( "\"%28x%2B3%29%28x-9%29+=+0\" Applying the zero product principle, you get:
\n" ); document.write( "x = -3 Discard this solution as the width can't be a negative value.
\n" ); document.write( "x = 9 This is the width of the original piece of cardboard.
\n" ); document.write( "x+2 = 11 This is the length of the original piece of cardboard.\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "V = (9-4)(11-4)(2) = (5)(7)(2) = 70
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