document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=674193>Question 674193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is 3 times as old as her daughter. 6 years ago, the sum if their ages is 36. Find the agenof the daughter and the mother. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #419046 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=419046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=daughter's age now; x-6=daughter's age 6 years ago<BR>\n" );
document.write( "Then 3x=mother's age now; 3x-6=mother's age 6 years ago<BR>\n" );
document.write( "Sooooo<BR>\n" );
document.write( "(x-6)+(3x-6)=36<BR>\n" );
document.write( "4x-12=36 add 12 to each side<BR>\n" );
document.write( "4x-12+12=36+12 collect like terms<BR>\n" );
document.write( "4x=48 divide each side by 4<BR>\n" );
document.write( "x=12-----daughter's age now<BR>\n" );
document.write( "3x=3*12=36------mother's age now<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "12-6+36-6=36<BR>\n" );
document.write( "6+30=36<BR>\n" );
document.write( "36=36\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );