document.write( "Question 60978: One bus traveles 20 km/hr faster than another. While the slower bus traveles 280 km the faster one goes 440 km. Find the speed of the faster bus.\r
\n" ); document.write( "\n" ); document.write( "a) 35 km/hr
\n" ); document.write( "b) 45 km/hr
\n" ); document.write( "c) 55 km/hr
\n" ); document.write( "d) 65 km/hr
\n" ); document.write( "e) none of these
\n" ); document.write( "

Algebra.Com's Answer #41904 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
I am guessing they traveled those distances in the same time (most likely scenerio.)
\n" ); document.write( "Distance = Rate * Time
\n" ); document.write( "Distance/Rate = Time
\n" ); document.write( "Times were equal:
\n" ); document.write( "Distance/Rate = Distance/Rate
\n" ); document.write( "Slower bus's distance: 280
\n" ); document.write( "Slower bus's rate: r
\n" ); document.write( "Faster bus's distance: 440
\n" ); document.write( "Faster bus's rate: r + 20
\n" ); document.write( "280/r = 440/(r + 20)
\n" ); document.write( "280(r + 20) = 440r
\n" ); document.write( "280r + 5600 = 440r
\n" ); document.write( "5600 = 160r
\n" ); document.write( "35 = r
\n" ); document.write( "Faster bus's rate: 35 + 20 = 55km/hr
\n" ); document.write( "
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