document.write( "Question 674115: Find the solution(s) to \"2%5Ek=sqrt%283%5E%28k-2%29%29\"
\n" ); document.write( "How do I get rid of the square root? Is that the first step? I'm not sure...
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Algebra.Com's Answer #419029 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
\"2%5Ek=sqrt%283%5E%28k-2%29%29\"
\n" ); document.write( "Square both sides
\n" ); document.write( "\"4%5Ek+=+3%5E%28k-2%29\"
\n" ); document.write( "k*log(4) = (k-2)*log(3) = k*log(3) - 2log(3)
\n" ); document.write( "k*log(4) - k*log(3) = -2log(3)
\n" ); document.write( "k(log(3) - log(4)) = log(9)
\n" ); document.write( "k*log(3/4) = log(9)
\n" ); document.write( "k = log(9)/log(0.75)
\n" ); document.write( "k =~ -7.63768
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