document.write( "Question 60985: Hopefully someone can help me with this one. Thanks!\r
\n" ); document.write( "\n" ); document.write( "x / x-2 = 2/x-3 we are solving for x.\r
\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #41900 by joyofmath(189)\"\" \"About 
You can put this solution on YOUR website!
\"x%2F%28x-2%29+=+2%2F%28x-3%29\"
\n" ); document.write( "Multiple both sides by \"x-3\"
\n" ); document.write( "Then \"x%28x-3%29%2F%28x-2%29+=+2\"
\n" ); document.write( "Now multiply both sides by \"x-2\"
\n" ); document.write( "Then \"x%28x-3%29+=+2%28x-2%29\"
\n" ); document.write( "Multiply both sides out.
\n" ); document.write( "Then \"x%5E2-3x+=+2x-4\"
\n" ); document.write( "Subtract 2x from both sides.
\n" ); document.write( "Then \"x%5E2-5x+=+-4\"
\n" ); document.write( "Now add 4 to both sides.
\n" ); document.write( "Then \"x%5E2-5x%2B4+=+0\"\r
\n" ); document.write( "\n" ); document.write( "This is a quadratic equation which factors:
\n" ); document.write( "\"%28x-1%29%28x-4%29+=+0\"
\n" ); document.write( "So, \"x=1\" and \"x=4\" are the two solutions.\r
\n" ); document.write( "\n" ); document.write( "To verify, plug 1 and 4 into the original equation \"x%2F%28x-2%29+=+2%2F%28x-3%29\"
\n" ); document.write( "\"1%2F%281-2%29+=+-1\" which is indeed equal to \"2%2F%28-2%29\"
\n" ); document.write( "And, \"4%2F%284-2%29+=+4%2F2+=+2\" which is indeed equal to \"2%2F%284-3%29\" which = 2
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