document.write( "Question 674056: How many gallons of a 40 percent solution must be mixed with 60 gallons of a 22 percent solution to obtain a solution that is 30 percent alcohol? \n" ); document.write( "

Algebra.Com's Answer #418997 by stanbon(75887) $\"\"$ $\"About$

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How many gallons of a 40 percent solution must be mixed with 60 gallons of a 22 percent solution to obtain a solution that is 30 percent alcohol?
\n" ); document.write( "-------
\n" ); document.write( "Quantity Equation: x + 60 = y
\n" ); document.write( "Percent Equation: 0.40x+0.22*60 = 0.30*y
\n" ); document.write( "------
\n" ); document.write( "Multiply thru 1st by 40
\n" ); document.write( "Multiply thru 2nd by 100
\n" ); document.write( "-------
\n" ); document.write( "40x + 40*60 = 40*y
\n" ); document.write( "40x + 22*60 = 30*y
\n" ); document.write( "------
\n" ); document.write( "Subtract and solve for \"y\"
\n" ); document.write( "18*60 = 10y
\n" ); document.write( "y = 108 gallons
\n" ); document.write( "----
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + 60 = y
\n" ); document.write( "x = 108-60
\n" ); document.write( "x = 48 gallons (amt. of 40% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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