document.write( "Question 673995: A disc jockey has 9 songs to play. Five are slow songs, and 4 are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 9 songs if
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document.write( "The songs can be played in any order.
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document.write( "The first song must be a slow song and the last song must be a slow song.
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document.write( "The first two songs must be fast songs.\r
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document.write( "Can you please explain this as you go. I not just out for an easy answer, I need insturction.PLEASE \n" );
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Algebra.Com's Answer #418970 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A disc jockey has 9 songs to play. Five are slow songs, and 4 are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 9 songs if \n" ); document.write( "The songs can be played in any order. \n" ); document.write( "There are 9 songs. \n" ); document.write( "1st song can be one of 9 \n" ); document.write( "2nd song can be one of 8 \n" ); document.write( "3rd song can be one of 7 \n" ); document.write( "etc. \n" ); document.write( "Ans 9! = 362,880 ways \n" ); document.write( "------------------------------------- \n" ); document.write( "The first song must be a slow song and the last song must be a slow song. \n" ); document.write( "1st song can be one of 5 \n" ); document.write( "Last song can be one of 4 \n" ); document.write( "Middle 7 songs can be in 7! = 5040 ways \n" ); document.write( "----- \n" ); document.write( "Ans: 5*4*5040 = 100,800 ways \n" ); document.write( "------------------------------------------- \n" ); document.write( "The first two songs must be fast songs. \n" ); document.write( "Ans: 4*3*7! = 12*5040 = 60,480 ways \n" ); document.write( "_____________________________________ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " \n" ); document.write( " |