document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=673803>Question 673803</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The 2010 American Census reported that 28.6% of American teens held part time jobs. Let p = .286 represent the proportion of American teens that have jobs. Find, if possible, the probability that a random sample of 30 American teens will have fewer than 20% who have part time jobs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #418965 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=418965\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 2010 American Census reported that 28.6% of American teens held part time jobs. Let p = .286 represent the proportion of American teens that have jobs. Find, if possible, the probability that a random sample of 30 American teens will have fewer than 20% who have part time jobs.<BR>\n" );
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document.write( "z(0.20) = (0.20-0.286)/sqrt[0.286*0.714/30] = -1.0424<BR>\n" );
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document.write( "P(p-hat < 0.20) = P(z < -1.0424) = normalcdf(-100,-1.0424) = 0.1486<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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