document.write( "Question 673644: find the area and the perimeter.
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document.write( "Perimeter is 50m
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document.write( "area is 62sq \n" );
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Algebra.Com's Answer #418871 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! ???Find the area and perimeter, and perimeter is 50m and area is 62sq??? \n" ); document.write( "... \n" ); document.write( "Find length and width? \n" ); document.write( "2(l) + 2(w) = 50, so l = (50-2w)/2 = 25-w \n" ); document.write( "(l)(w) = 62, \n" ); document.write( "... \n" ); document.write( "(25-w)w = 62 \n" ); document.write( "25w - w^2 = 62 \n" ); document.write( "0 = w^2 - 25w + 62 \n" ); document.write( "... \n" ); document.write( "w^2 - 25w + 156.25 = -62 + 156.25 \n" ); document.write( "... \n" ); document.write( "(w-12.5)^2 = 94.25 \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "w - 12.5 = +/- \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "w = 12.5 + 9.71 \n" ); document.write( "w = 12.5 - 9.71 \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "..................... \n" ); document.write( "Delighted to help. \n" ); document.write( "-Reading Boosters \n" ); document.write( "Website: www.MyHomeworkAnswers.com \n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( " |