document.write( "Question 673644: find the area and the perimeter.
\n" ); document.write( "Perimeter is 50m
\n" ); document.write( "area is 62sq
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Algebra.Com's Answer #418871 by ReadingBoosters(3246)\"\" \"About 
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???Find the area and perimeter, and perimeter is 50m and area is 62sq???
\n" ); document.write( "...
\n" ); document.write( "Find length and width?
\n" ); document.write( "2(l) + 2(w) = 50, so l = (50-2w)/2 = 25-w
\n" ); document.write( "(l)(w) = 62,
\n" ); document.write( "...
\n" ); document.write( "(25-w)w = 62
\n" ); document.write( "25w - w^2 = 62
\n" ); document.write( "0 = w^2 - 25w + 62
\n" ); document.write( "...
\n" ); document.write( "w^2 - 25w + 156.25 = -62 + 156.25
\n" ); document.write( "...
\n" ); document.write( "(w-12.5)^2 = 94.25
\n" ); document.write( "\"sqrt%28w-12.5%29%5E2\" = +/- \"sqrt%2894.25%29\"
\n" ); document.write( "...
\n" ); document.write( "w - 12.5 = +/- \"sqrt%2894.25%29\"
\n" ); document.write( "\"w=12.5%2B-sqrt%2894.25%29\"
\n" ); document.write( "...
\n" ); document.write( "w = 12.5 + 9.71
\n" ); document.write( "w = 12.5 - 9.71
\n" ); document.write( "...
\n" ); document.write( "\"highlight_green%2822.21%29\" and \"highlight_green%282.79%29\"
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\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
\n" ); document.write( "Website: www.MyHomeworkAnswers.com
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