document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60920>Question 60920</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937760/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> i have to find the coordinates of the vertex of y=1/2x^+3x-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41886 by </B><A HREF=/tutors/aboutme.mpl?userid=pvaka><B>pvaka(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pvaka><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i have to find the coordinates of the vertex of y=1/2x^2+3x-7\r<BR>\n" );
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document.write( "Find the x coordinate first by using the formula x=-b/2a and then substitute that value fo x in the original equation, then solve for the y coordinate.\r<BR>\n" );
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document.write( "y=ax^2+bx+c====>>1/2x^2+3x-7<BR>\n" );
document.write( "a=1/2,b=3,c=-7<BR>\n" );
document.write( "x=-b/2a==>>-(3)/2(1/2)=-3/1<BR>\n" );
document.write( "x=-3<BR>\n" );
document.write( "y(-3)=1/2(-3)^2+3(-3)-7<BR>\n" );
document.write( "y=-23/2<BR>\n" );
document.write( "Vertex coordinates (-3,-23/2)\r<BR>\n" );
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document.write( "Pvaka </SPAN>\n" );
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