document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60945>Question 60945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can anyone help getting this set up and solved?  Thanks\r<BR>\n" );
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document.write( "Solve 5x^2 + 2x - 1 = 0\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41881 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x^2+2x-1=0 using the quadratic equation we get<BR>\n" );
document.write( "x=(-b+-sqrt[b^2-4ac])/2a<BR>\n" );
document.write( "x=(-2+-sqrt[4-4*5*-1])/2*5<BR>\n" );
document.write( "x=(-2+-sqrt[4+20])/10<BR>\n" );
document.write( "x=(-2+-sqrt24)/10<BR>\n" );
document.write( "x=(-2+-4.9)/10<BR>\n" );
document.write( "x=(-2+4.9/10<BR>\n" );
document.write( "x=2.9/10<BR>\n" );
document.write( "x=.29 solution<BR>\n" );
document.write( "x=(-2-4.9)/10<BR>\n" );
document.write( "x=-6.9/10<BR>\n" );
document.write( "x=-.69 solution<BR>\n" );
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