document.write( "Question 673652: the digit at the tens place of a two digit number is three times the digit at ones place.if the sum of this number and the formed by reversing its digit is 88, find the number .
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Algebra.Com's Answer #418783 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let x = the 10's digit
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\n" ); document.write( "10x+y = the number
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\" the digit at the tens place of a two digit number is three times the digit at ones place.\"
\n" ); document.write( "x = 3y
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\n" ); document.write( "\"The sum of this number and the number formed by reversing its digit is 88,\"
\n" ); document.write( "(10x + y) + (10y + x) = 88
\n" ); document.write( "10x + x + 10y + y = 88
\n" ); document.write( "11x + 11y = 88
\n" ); document.write( "simplify, divide by 11
\n" ); document.write( "x + y = 8
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\n" ); document.write( "You should be able to do it now. (Replace x with 3y)\r
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